er einhver sem veit bestu lausnina fyrir þetta í c++
gráður í radíana og öfugt
#include <iostream> #include "math.h" using namespace std; float deg2rad(float deg) { return deg * M_PI / 180.0; } float rad2deg(float rad) { return rad * 180.0 / M_PI; } int main() { float tala; int op = -1; while ((op < 0) || (op > 2)) { cout << "0. to exit the program." << endl; cout << "1. for radians to degrees." << endl; cout << "2. for degrees to radians." << endl; cout << "Type in your selection: "; cin >> op; cout << endl; } if (op == 1) { cout << "Type in a nr. in radians: "; cin >> tala; cout << tala << " radians are " << rad2deg(tala) << " in degrees." << endl; } else if (op == 2) { cout << "Type in a nr. in degrees: "; cin >> tala; cout << tala << " degrees are " << deg2rad(tala) << " in radians." << endl; } if (op == 0) return 0; cout << endl; system("pause"); return 0; }
math.h
#define M_E 2.71828182845904523536028747135266250 /* e */
#define M_LOG2E 1.44269504088896340735992468100189214 /* log 2e */
#define M_LOG10E 0.434294481903251827651128918916605082 /* log 10e */
#define M_LN2 0.693147180559945309417232121458176568 /* log e2 */
#define M_LN10 2.30258509299404568401799145468436421 /* log e10 */
#define M_PI 3.14159265358979323846264338327950288 /* pi */
#define M_PI_2 1.57079632679489661923132169163975144 /* pi/2 */
#define M_PI_4 0.785398163397448309615660845819875721 /* pi/4 */
#define M_1_PI 0.318309886183790671537767526745028724 /* 1/pi */
#define M_2_PI 0.636619772367581343075535053490057448 /* 2/pi */
#define M_2_SQRTPI 1.12837916709551257389615890312154517 /* 2/sqrt(pi) */
#define M_SQRT2 1.41421356237309504880168872420969808 /* sqrt(2) */
#define M_SQRT1_2 0.707106781186547524400844362104849039 /* 1/sqrt(2) */